Roomcap**
-THEORY Remarks1**

7.July 2014**UPD: July 29th 14****
**

Felix Meyer HB9ABX

7.July 2014

Felix Meyer HB9ABX

Calculations and explanations to/

Radiation ResistanceEfficiency

The radiation resistance is often wrongly understood, with the opinion, that an

antenna with the higher radiation resistance means a higher efficiency.

Many theory books and teachers say, that a higher radiation resistance Rs = Rrad (serial)

leads to a better antenna.

(depends of the type of dipole) (vereinfacht = simplified)

Here the formula Rrad =radiation resistance

And: Ps = Radiation power (Rs = Rrad)

Radiation power Ps: into the far-field radiated power radiated:

This fomula leads to the wong conclusion: higher Rs = higher radiation power

This would means, that you always would have the same current I ...

therefore a construction is searched, where a higher Rs is searched!

Thereby theefficiency can to decrease!

The the wrong conclusion made alsoON4UN (Low Band DX), and thereby some

super large antennas originated, who did not offer any better solutions.

(Here the equivalent circuit, where Rrad (= Rs) and Rloss (= Rv) are in serial.

X stays for the inductiv or capacitiv reactance)

The best antenna is found by seaching the highest efficiency eta(A).

Here the formula of the efficiency:

(Rs = radiation resistance, Rv = total loss-resistance)

This most important:greatest relation of Rs to Rv!

Note: The amount of Rs alone says nothing about the quality of the antenna.

Therefore the efficience of the Roomcap is high, as we have a high relation Rs/Rv.

To obtain a high eta, look to have a low Rv.

The loss-resistance Rv = addition of ground-loss-resistance and loss of antenna.

Here you see the ground loss Rg:

Most at aclassic antennais gone lossed in the ground, because the loss of the

antenna current is lost on the way back to the antenna in ground.

Therefore, they recommend to lay many radials, in order to lower the ground-

resistance.

Rg = ground-resistance

Here you see, how the Rg depends from the number of the radials, and from the length

of the radials.

The spatial progation of the ways of the return current depends from the length

of the antenna. The most ground-current fields come back within a distance

of 1.5 length of the antenna.

Therefore, as smaller the antenna, so shorter way goes the ground-current.

Therefore, we need for the Roomcap a short length for the "counter plane".

Besides we do not use radials, instead of them we have a "counter plane", in the length

of about 2.25m.

Thereby the Rg of a "classic antenna" is between 5 to 30 Ohms.

We obtain a ground resistance Rg below 1 Ohm for the Roomcap! <<<

Next step:(in PDF)

Here to the Rs radiation resistance

Above indicated formulas, who result by derivation of Maxell's equations for the

"current in wire".

The table from D.Jefferies (University of Surrey) here

there you see, that the Rrad is smaller than 0.5 Ohms for L/lambda of 1/20 wave length,

(L = length of the antenna) in according with the "current in wire" method.

With the method "current over planes" with an area of 1m x 1m size, I obtain a

radiation resistance Rs of abt. 5 Ohms at 7 MHz.

More than 10 times more !

And now you apply the formulas to obtain the efficiency eta(A).

The result tells, why this good signal reports results for Roomcap!

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Now have a look at W8JI, the best known expert from ARRL for antennas.

He published articles about short antennas. See HERE

He obtaines a Rg (ground loss resistance) of 11 Ohms. Study his report, and read

what efficiency is calculated with "current in wire" method.

This demonstrates, that today we need a progress after we are using "current in

wire" over 110 years. Since Heinrich Hertz and Guglielmo Marconi.

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>>> NEW: 10th July 2014

Here we see the precisecalculation of the efficient: Roomcap

This antenna is working as parallel circuit, therfore one has to learn how

to calculate in parallel equivalent circuit diagram.

Here we work with parallel radiation resistance.

Below you see an extract of the analyse :

And note:The correct value of the SWR is 2.62 for bandwidth reading at F1 and F2!

I ask you to refresh your electric and math knowledge to understand the calculation of

the diagram, and to understand the correlation of the different parts.

You have to study of the referenc above (VE2AZX-Q-factor.pdf).

PS: The complete analyse you find HERE

However, then you can learn a big amount.

I ask you to write me, if you have more questions.

It's ringing ? >>> I hope!

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